
Choi S.
asked 11/28/22What is the orbital speed of the planet ? (G = 6.673 * 10 ^ - 11 * N * m ^ 2 / k * g ^ 2)
whats the answer? help
1 Expert Answer
For orbit of Earth around the Sun, establish:
Gravitational Constant G-------------------------------6.6725985E-11 N•m2/kg2
Solar Mass Msun------------------------------------------1.991E30 kg
Earth Mass Mearth----------------------------------------5.98E24 kg
Earth's Solar Orbital Radius Rearth-------------------1.496E11 m
Earth's Period For 1 Solar Orbit Tearth---------------3.156E7 s
Orbital Speed Of The Planet (Vearth)-----------------To Be Determined
Earth's orbit around the Sun is extremely close to a circle, but note that the
Sun is not at the dead center of this orbital path.
From the inverse-square law for circular orbits, equate the gravitational force by the Sun on Earth to the centripetal force required to maintain Earth's "circular" path around the star:
GMsunMearth/Rearth2 = MearthVearth2/Rearth
Then Vearth is isolated as (GMsun/Rearth)0.5 which goes to 29800.07314 m/s.
Compare this last value to 2πRearth/Tearth or 2π(1.496E11)/3.156E7 which gives 29783.41324 m/s.
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Sidney P.
needs more data! like mass of the object being orbited, and distance of planet from this object. Then v = sqrt(G M/ r)11/29/22