Evaluate the expression under the given conditions. sin(𝜃 − 𝜑); tan(𝜃) = 12/5 , 𝜃 in Quadrant III, sin(𝜑) = − 3* sqrt10/10 , 𝜑 in Quadrant IV

Answer 1

sin(T-P)

= (12/13)(1/sqr10)- (-3/sqr10)(5/13)

=(12-15)/(13)(sqr10)

=-3/13sqr10

=-3sqr10/130 = about ..073

T= tan^-1(12/5)= about 180-67.4= 112.6

P =sin^-1(-3sqr10/10) = 330-71.6 = 258.4

T-P=112.6+71.6 = 184.23

sin(184.23)=.073