
Yefim S. answered 11/22/22
Math Tutor with Experience
a) [sqrt(3) (coś pi/18 +isin pi/18)]^6 = 27(cosπ/3 + isinπ/3) = 27/2 + 27√3/2i = 27eiπ/3
b) (1-sqrt(5)i)^8 = {√6(cos5.1329 + isin5..1329)]8 = 64(cos41.0634 + isin41.0634) = -1264 - 286.2167i =
1296e41.0634i
r = √(1 + 5) = √6; tanθ = -√5/1 = - √5; θ = 2π - tan-1√5 = 5.1329