A shot-putter throws the shot mass=7.3kg with an initial speed of 14.4m/s at angle 34 degrees with horizontal.Calculate the horizontal distance travelled by the shot if it is leaves the athlete's hand at height of 2.10m above the ground.
The shot height depends on time like y = y₀ + st sinθ – gt²/2 so by the quadratic formula, it reaches y → 0 at t → (s sinθ + √(s²sin²θ + 2gy₀))/g. The range is then x = st cosθ.