HELP ME WITH PROJECTILE MOTION ASAP!

Question

The speed of an arrow fired from a compound bow is about 12 m/s. An archer sits astride his horse and launches an arrow into the air, elevating the bow at an angle of 54◦ above the horizontal and 3 m above the ground. What is the arrow’s range? The acceleration of gravity is 9.81 m/s 2 . Assume the ground is level and ignore air resistance. Answer in units of m.

Answer 1

V_horizontal = 12cos54 , V_vertical = 12sin54

X_o = 0, y_o = 3

When it lands, y = 0; We can change it with 'h' and find 't'

h(t) = h₀ + (12sin54 x t) + (1/2 x g x t²)

0 = 3 + 9.7t - 4.9t²

t =~ 2.25s

Range = D_(horizontal) = 12cos54 x t =~ 15.87 ~ 16m