
Yefim S. answered 01/04/23
Math Tutor with Experience
x = 12.4cos50°t; y = 7.4 + 12.4sin50°t - 4.9t2 = 0; 4.9t2 - 9.5t - 7.4 = 0; t = 2.53 s; x = 12.4cos50°·2.53 = 20.17 m
Eleanor J.
asked 11/21/22A 0.25 kg projectile is fired into the air from the top of a 7.4 m cliff above a valley. Its initial velocity is 12.4 m/s at 50◦ above the horizontal. How long is the projectile in the air? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of s. How far from the bottom of the cliff does the projectile land? Answer in units of m.
Yefim S. answered 01/04/23
Math Tutor with Experience
x = 12.4cos50°t; y = 7.4 + 12.4sin50°t - 4.9t2 = 0; 4.9t2 - 9.5t - 7.4 = 0; t = 2.53 s; x = 12.4cos50°·2.53 = 20.17 m
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