0.2a + 0.35b + 0.8c = 108(0.4)
a + b + c = 108
c = 2b
0.2a + 0.35b + 0.8(2b) = 43.2
0.2a + 0.35b + 1.6b = 43.2
0.2a + 1.95b = 43.2
a + b + 2b = 108
a + 3b = 108
a = 108 - 3b
0.2(108 - 3b) + 1.05b = 43.2
I'm leaving the rest to you. Go!
Alice R.
asked 11/20/22A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 35% and the third contains 80%. They want to use all three solutions to obtain a mixture of 108 liters containing 40% acid, using 2 times as much of the 80% solution as the 35% solution. How many liters of each solution should be used?
0.2a + 0.35b + 0.8c = 108(0.4)
a + b + c = 108
c = 2b
0.2a + 0.35b + 0.8(2b) = 43.2
0.2a + 0.35b + 1.6b = 43.2
0.2a + 1.95b = 43.2
a + b + 2b = 108
a + 3b = 108
a = 108 - 3b
0.2(108 - 3b) + 1.05b = 43.2
I'm leaving the rest to you. Go!
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