
Dayv O. answered 11/19/22
Attentive Reliable Knowledgeable Math Tutor
know CE=3 (opposite side from 30 degrees is half hypotenuse in right triangle)
BE=√(62-32)=√27=3√3
know BD=6/√2=3√2 (BCD is a 45 degree right triangle)
BD2+BD2=62
DE=BE-BD
Sophia C.
asked 11/19/22Using the special triangles, determine the exact value of segment DE. Segments d= BA and e = BC have length 6. Express your answer in simplified radical form.
Dayv O. answered 11/19/22
Attentive Reliable Knowledgeable Math Tutor
know CE=3 (opposite side from 30 degrees is half hypotenuse in right triangle)
BE=√(62-32)=√27=3√3
know BD=6/√2=3√2 (BCD is a 45 degree right triangle)
BD2+BD2=62
DE=BE-BD
Yefim S. answered 11/19/22
Math Tutor with Experience
BE = 3√3; BD = 3√2; so, DE = 3(√3 - √2)
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