A ball thrown horizontally at 35 m/s travels a horizontal distance of 59 m before hitting the ground. Air resistance is negligible. From what height was the ball thrown?

Answer 1

Since the ball was thrown horizontally, we know that the ball was in the air for a total of 59/35 seconds. From there, we can calculate the height by using the equation x(t) = 1/2 at² + x(0). In this case, the acceleration is from gravity, so a will be -9.8 m/s². From here, you should be able to solve for x(0), which is the initial height.