Projectile Motion

Question

Assume: A 78 g basketball is launched at an angle of 46.7 ◦ and a distance of 18.6 m from the basketball goal. The ball is released at the same height (ten feet) as the basketball goal’s height. A basketball player tries to make a long jump-shot as described above. The acceleration of gravity is 9.8 m/s 2 . What speed must the player give the ball? Answer in units of m/s.

Answer 1

x = v₀cos46.7°·t = 18.6; y = h + v₀sin46.7°·t - gt²/2 = h; t = 0(moment of launching) or t = 2v₀sin46.7°/g;

2v₀²cos46.7°sin46.7°/g = 18.6; v₀ = (18.6·9.8/sin93.4°)^1/2 = 13.51 m/s