Dominick O. answered 09/06/25
Introductory Physics 1 Tutor for 2 years
There is an equation associated with the Doppler effect which explains sound frequencies by observer which goes: f = fo ((V +/- Vo)/(V -/+ Vs)). f is the observed frequency, fo is the true frequency, V is the velocity of the sound waves, Vo is the observer's velocity, and Vs is the velocity of the source. For the components of the equation, (V + Vo) is when observer is approaching the source, (V - Vo) is when the observer is leaving, (V - Vs) is when the source approaches the observer, and (V + Vs) is when the source leaves the observer. Vo or Vs = 0 if the observer or source isn't moving. The V (speed of sound) is 1235 km/h.
a. Here the equation is f = 1280 ((1235)/(1235-110.0)) which is solved for f = 1405 hz
b. Here it would be f = 1280 ((1235)/(1235+110.0)), so f = 1175 hz
c. Now the source and observer approach each other, so it's f = 1280 ((1235 + 110.0)/(1235 - 110.0)) so f = 1530 hz
d. Now the source and observer leave each other, f = 1280 ((1235 - 110.0)/(1235 + 110.0)) = 1071 hz
e. The observer is leaving a source that's approaching, so f = 1280 ((1235 - 90.00)/(1235 - 110.0)) = 1303 hz
f. Now the observer is approaching and the source is leaving. f = 1280 ((1235 + 90.00)/(1235 + 110.0)) = 1261 hz