Please solve this physics problems

Question

A mass m₁ = 4.6 kg rests on a frictionless table and connected by a massless string to another mass m₂ = 5 kg. A force of magnitude F = 43 N pulls m₁ to the left a distance d = 0.85 m.

1)

How much work is done by the force F on the two block system?

J 

2)

How much work is done by the normal force on m₁ and m₂?

J 

3)

What is the final speed of the two blocks?

m/s 

4)

How much work is done by the tension (in-between the blocks) on block m₂?

J 

5)

What is the tension in the string?

N 

6)

What is the NET work done on m₁?

Answer 1

1.The total work done on the systerm is

W=Force. Displacement

W=43 * 0.85

W=36.55 J ,This is the work done by the force on the system the total force F=43 N acting on the system not only on m1