Inactive Tutor answered 11/10/22
x = v0cosαt; y = v0sinαt - gt2/2; t = 0 or t = 2v0sinα/g; x = v0cosα·2v0sinα/g, x = v02sin2α/g; xmax = v02/g; v02 = g·
xmax;; 02 - gxmax = - 2gh; h = xmax/2 ]= 101m/2 = 50.5 m
maxsin2α = 1; 2α = 90°; α = 45°
Elizabeth G.
asked 11/10/22A man can throw a ball a maximum horizontal distance of 101 m. The acceleration of gravity is 9.8 m/s 2 .
Inactive Tutor answered 11/10/22
x = v0cosαt; y = v0sinαt - gt2/2; t = 0 or t = 2v0sinα/g; x = v0cosα·2v0sinα/g, x = v02sin2α/g; xmax = v02/g; v02 = g·
xmax;; 02 - gxmax = - 2gh; h = xmax/2 ]= 101m/2 = 50.5 m
maxsin2α = 1; 2α = 90°; α = 45°
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Elizabeth G.
It says the answer is incorrect. The 2 was a typo. Please help11/10/22