First change the variable as: y = sec(x).
Therefore: y2 + 5y -14=0 .
This can be decomposed as: (y-2)(y+7)=0, which means y = 2 or y=-7.
Now x = arcsec(y), and so: x = arcsec(2) = 60o = 1.047 radians, or x=arcsec(-7) = 98.210 = 1.71 radians.
Lala L.
asked 11/09/22Solve the equation. (Enter your answers as a comma-separated list. Use n as an arbitrary integer. Enter your response in radians.)
sec2(x) + 5 sec(x) − 14 = 0
x=
First change the variable as: y = sec(x).
Therefore: y2 + 5y -14=0 .
This can be decomposed as: (y-2)(y+7)=0, which means y = 2 or y=-7.
Now x = arcsec(y), and so: x = arcsec(2) = 60o = 1.047 radians, or x=arcsec(-7) = 98.210 = 1.71 radians.
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