
Yefim S. answered 11/09/22
Math Tutor with Experience
csc2x = 5; cot2x = 4; cotx = ±2; tanx = ±1/2;
tanx= 1/2; x = tan-1(1/2) = 0.464 or x = tan-1(1/2) + π = 3.605
tanx = - 1/2; x = - tan(1/2) + π = 2.678 or x = - tan-1(1/2) + 2π = 5.820
Lala L.
asked 11/09/22Use a graphing utility to approximate (to three decimal places) the solutions of the equation in the interval [0, 2𝜋). (Enter your answers as a comma-separated list.)
csc2(x) − 5 = 0
x=
Yefim S. answered 11/09/22
Math Tutor with Experience
csc2x = 5; cot2x = 4; cotx = ±2; tanx = ±1/2;
tanx= 1/2; x = tan-1(1/2) = 0.464 or x = tan-1(1/2) + π = 3.605
tanx = - 1/2; x = - tan(1/2) + π = 2.678 or x = - tan-1(1/2) + 2π = 5.820
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.