
Yefim S. answered 11/08/22
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- r2cos2θ = 4rsinθ; r = 4tanθsecθ
- 4r2cos2θ·rsinθ = 1; r3 = 1/(4sin2θcosθ)
Katelyn A.
asked 11/08/22Yefim S. answered 11/08/22
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Mark M. answered 11/08/22
Mathematics Teacher - NCLB Highly Qualified
r sin θ = x
r cox θ = y
Substitute and simplify.
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