When copper metal is added to silver nitrate in solution,silver metal and copper 2 nitrate are protected. What mass of silver is produced from 100.g of Cu?

Answer 1

To find the mass of silver produced when 100 g of copper (Cu) reacts with silver nitrate (AgNO3) to form silver (Ag) and copper(II) nitrate (Cu(NO3)2), you can use stoichiometry and the balanced chemical equation for the reaction.

First, you need to write the balanced chemical equation for the reaction:

Cu + 2AgNO3 → 2Ag + Cu(NO3)2

Now, let's determine the molar mass of each substance involved:

- Molar mass of Cu (copper) = 63.55 g/mol

- Molar mass of AgNO3 (silver nitrate) = 169.87 g/mol

- Molar mass of Ag (silver) = 107.87 g/mol

The balanced equation tells us that 1 mole of Cu reacts to produce 2 moles of Ag. So, you need to find out how many moles of Cu you have in 100 g of Cu:

Number of moles of Cu = (mass of Cu) / (molar mass of Cu)

Number of moles of Cu = (100 g) / (63.55 g/mol) ≈ 1.573 moles

Now, using the mole ratio from the balanced equation, we know that 1 mole of Cu produces 2 moles of Ag. So, you'll produce twice as many moles of Ag as you have moles of Cu:

Number of moles of Ag = 2 × (number of moles of Cu)

Number of moles of Ag = 2 × 1.573 moles ≈ 3.146 moles

Finally, calculate the mass of silver produced using the number of moles of Ag and the molar mass of Ag:

Mass of Ag produced = (number of moles of Ag) × (molar mass of Ag)

Mass of Ag produced = 3.146 moles × 107.87 g/mol ≈ 339.21 g

So, approximately 339.21 grams of silver will be produced from 100 grams of copper.