Tom B. answered • 11/07/22
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Do you mean write an equation that has a single expression containing a, b and c? If so, here's one way to do it:
Taking the arcsin of both sides of sin t = a, it becomes arcsin (sin t) = arcsin a, which is t = arcsin a.
Similarly, t = arccos b and t = arctan c, and so you could write:
t = (arcsin a + arccos b + arctan c) / 3
Tom B.
Thanks for sending this. The concept here is that trig functions repeat every 2pi so sin t = sin (t+2pi) = sin (t+4pi) = etc. So sin (t+4pi) = sin t = a, and cos (t+8pi) = cos t = b. But what is tan (t+3pi), which is equal to tan (t+pi)? It is helpful to think of tan = sin / cos. Also, sin(t+pi)=-sin(t) and cos(t+pi)=-cos(t) So, tan(t+pi) = sin(t+pi)/cos(t+pi) = -sin(t)/-cos(t) = tan t . So tan(t+3pi) = tan t = c. So the answer to question would simply be: a - b + c
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11/07/22
Quinn M.
oh gosh I forgot to add the equation sin(t+4π)−cos(t+8π)+tan(t+3π)11/07/22