Michael M. answered 13d
AP & College Physics • PhD • Simplifying Physics Step by Step
Hi Bristan
For flowing water you can use Bernoulli's equation:
Ptop+ρghtop+ρvtop2/2=Pbottom+ρghbottom+ρvbottom2/2
In your case:
- pressure at the top and bottom are the same 1 atm (atmospheric pressure, since both are open to atmosphere),
- velocity at the top is the speed by which the liquid level will drop. Since it is very wide container, the speed of the water level dropping there will be close to zero.
- You can set hbottom as zero height, and your equation simplifies to:
ρghtop=ρvbottom2/2
You don't even need to know the density of your fluid because it cancels:
ghtop=vbottom2/2
Solve for vbottom
vbottom=(2ghtop)1/2
You can also get this equation from conservation of energy for an object freely falling a distance h: this is why we sometimes refer Bernoulli's law as conservation of energy for fluids. I will leave the last part for you to do: just plug in the height (htop=5.8 m) and the value of g=9.8 m, and you should get your answer.
Remember that this works only if you are told that the area of the container ("very wide") is much larger than the cross sectional area of the opening (hole) through which the liquid flows.