Daniel B. answered 11/06/22
A retired computer professional to teach math, physics
Let
h = 21 m he the desired height,
d = 1000 kg/m³ be the density of water,
g = 9.81 m/s² be gravitational acceleration,
p (to be calculated) be the pressure in the hose.
We are going to use conservation of energy.
The potential energy of the water at height h comes from its pressure energy in the hose.
Consider a small volume V of water.
Its mass is
m = Vd
Its pressure energy is pV.
Its potential energy at height h is mgh.
Conservation of energy gives the equation
pV = mgh
p = mgh/V = dgh = 1000×9.81×21 = 206,000 N/m² ≈ 2 atm