what is the acceleration given to a 25kg block of cement when it is pulled sideways with a net force of 480N? draw the free body diagram for the forces acting on the block of cement

Question

This is a question on a homework assignment that I can't figure out. I'm not sure how to set up the equation

answer the problem by using the equation for force (F=ma) and (W=mg)

Answer 1

As there doesn't appear to be any friction, use f = ma

a = f/m = 480/25 = 19.2 m/s². There is on horizontal force = 480 N. Downward force - weight = mg = 25 *9.8 = 245 N. The normal contact foce f_n = 245 N upwards