Arthur D. answered 03/19/15
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sin2x/sec2x-1
sin2x/(1/cos2x)-1
sin2x/(1/cos2x)-(cos2x/cos2x)
sin2x/[(1-cos2x)]/[cos2x]
sin2xcos2x/(1-cos2x)
sin2xcos2x/sin2x because sin2x+cos2x=1
cancel the sin2x's
cos2x is the simplest form