stuck on this one new to precalculus

Question

In the year 1985, a house was valued at $106,000. By the year 2005, the value had appreciated to $149,000. What was the annual growth rate between 1985 and 2005? Assume that the value continued to grow by the same percentage. What was the value of the house in the year 2010?

The annual growth rate between 1985 and 2005 is %

The value of the house in the year 2010 is 

Answer 1

The standard growth rate formula

E = B(1 + r)^n

Where B is the beginning value

E is the end value

n is the number of time periods

r is the growth rate

Here we know B, E and n and need to find r

149,000 = 106,000(1 + r)^20

(1 + r)^20 = 149/106 = 1.40566

1 + r = 1.01717

r = 0.01717 or about 1.72% growth

Using this growth rate for 25 years gives

E = 106,000(1.01717)^25 = 162,239

In 2010 the value the house is approximately $163,239