Find the solutions of the equation in the interval [−2𝜋, 2𝜋].

Question

Find the solutions of the equation in the interval [−2𝜋, 2𝜋]. Use a graphing utility to verify your results. (Enter your answers as a comma-separated list.)

csc(x) = 23

3

(csc(x)=2 suqareroot 3 over 3)

x=

Answer 1

cscx = 2√3/3; sinx = √3/2; x = π/3, 2π/3, - 5π/3, - 4π/3