
Yefim S. answered 11/01/22
Math Tutor with Experience
a) sin(2sin-1(1/√2)) = sin(2·π/4 = sin(π/2) = 1
b) cot[2cos-1(-3/5)]; Let cos-1(-3/5) = α; then cosα = - 3/5 and α in Quadrant II.
cot(2α) = cos2α/sin2α; cos2α = 2cos2α -1 = 2(-3/5)2 - 1 = - 7/25;
sin2α = 2sinαcosα = 2(- 3/5)√(1 - 9/25) = - 6/5·4/5 = - 24/25;
cot2α = (- 7/25)(- 25/24) = 7/24
Answer: 7/24