Krunal G. answered 10/26/22
Experienced High School Tutor Specializing in Physics
Given
m1= 7100 kg
v1i= 12.0 m/s
v2i= 0 m/s
mf= m1+m2
vf= 4.60 m/s
We solve for v2f and plug in the given values to determine the answer
p1i+p2i= pf
⌋
m1v1i+m2v2i = mfvf
m1v1i+m2v2i = (m1+m2)vf
m1v1i+m2v2i/vf = m1+m2
∴ m2 = ⌈m1v1i+m2v2i/vf⌋- m1
=⌊ (7100 kg)(12.0 m/s)+(m2)(0 m/s) / 4.60 m/s⌋ - 7100 kg
= (18521.73kg)-(7100 kg)
= 11421.73 kg
m2 ≈11422 kg
Mass of the second car is 11422 kg.