
Lala L.
asked 10/23/22Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond for the given total investment and annual return.
You invest in AAA-rated bonds, A-rated bonds, and B-rated bonds. The average yields are 4.5% on AAA bonds, 5% on A bonds, and 9% on B bonds. You invest twice as much in B bonds as in A bonds. Let x, y, and z represent the amounts invested in AAA, A, and B bonds, respectively.
x | + | y | + | z | = | (total investment) |
0.045x | + | 0.05y | + | 0.09z | = | (annual return) |
2y - z = 0
Use the inverse of the coefficient matrix of this system to find the amount invested in each type of bond for the given total investment and annual return. (Round your answers to the nearest cent.)
Total Investment- $12,000 Annual Return- $815
amount invested in AAA-bonds $____ | amount invested in A-bonds $____ | amount invested in B-bonds $____ |
1 Expert Answer
Raymond B. answered 01/31/23
Math, microeconomics or criminal justice
.09x +.05y + .045z = 815
y - 2z = 0
x + y + z = 12000
.09 .05 .045 | 815
0 1 -2 | 0
1 1 1 | 12000
after row operations
1 0 0 | 5885
0 1 0 | 2038
0 0 1 | 4077
$5885 in AAA
$ 2038 in A
$ 4077 in B
rounded approximations, ignoring cents
or solve by substitution & elimination
.09x + .05y + .045z = 815
z =2y
.09x +.05y +.09y = 815
.09x +.14y = 815
x + y + z = 12000
x + y +2y = 12000
x +3y = 12000
.09x +.27y = .09(12000) = 1080
.27y -.14y = 1080-815
.13y = 265
y = 265/.13 =$2038.46 invested in A bond
z = 2y = $4076.92 invested in B bonds
x = 12000-y-z = $5884.62 in AAA bonds
check the answers:
.09(5884.62) + .05(2038.46) + .045(4076.92)
= 529.71 + 101.92 + 183.46
= 815.09
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Mark M.
A less complicated way is to solve using a system of three equations. Why is the inverse matrix required?10/24/22