Raymond B. answered • 10/10/22
Tutor
5
(2)
Math, microeconomics or criminal justice
2x^2 + 2y^2 +4x -4y +4 = 0
x^2 +y^2 +2x -2y =-2
complete the squares
x^2 +2x +1 + y^2 -2y +1 = -2+1+1
(x+1)^2 + (y-1)^2 = 0^2 is standard form for a circle's equation
is a (degenerate) circle, with center (-1,1) and radius = sqr(0^2) = 0
the "entire" graph is just one point (-1,1), x=-1, y=1
check the answer
2(-1)^2 + 2(1)^2 +4(-1)-4(1) +4 =0
2+2-4-4+4 = 0
