given the terminal side of an angle in standard position is at (-6,-8) find and solve for the sin,cos and cot.

Question

given the terminal side of an angle in standard position is at (-6,-8) find and solve for the sin,cos and cot.

Answer 1

P = (-6,-8)  ==>  r = sqrt(x^2 + y^2) = sqrt(36 + 64) = sqrt(100) = 10 

 

sin(theta) = y/r = -8/10 = -4/5

 

cos(theta) = x/r = -6/10 = -3/5

 

cot(theta) = x/y = -6/-8 = 3/4