Here, you have 270cos 185° + 35cos 335° equal to -237.2517959.
Also, calculate 270sin 185° + 35sin 335° equal to -38.3236897.
Then take [(-237.2517959)2 + (-38.3236897)2]0.5 or 240.3271101 as
the magnitude of the resultant velocity vector.
The direction of the resultant velocity vector is given by the arctangent
of {-38.3236897 ÷ -237.2517959} which gives for Quadrant III (180 + 9.1758267)°
or 189°10'32.98" in Degrees, Minutes, and Seconds.
The resultant velocity vector then amounts to 240.3271101 meters per second at
189°10'32.98"or 9°10'32.98" south of west.