Assuming theta is the outer segment’s angle with the horizontal ceiling, and phi is the inner segment’s angle with the horizontal:
Each of the four segments has length:
L = 56.6 / 4 = 14.15 cm
Each inner segment supports half the middle object's weight. Each outer segment supports that plus one additional object's weight.
The vertical tension components therefore have a 3:1 ratio, while the horizontal components are equal:
tan(theta) = 3 * tan(phi)
(a) Find phi:
phi = arctan(tan(69 degrees) / 3)
phi = 40.97 degrees
phi ≈ 41.0 degrees
(b) Add the horizontal projections of all four segments:
d = 2L * cos(theta) + 2L * cos(phi)
d = 2(14.15) * [cos(69 degrees) + cos(40.97 degrees)]
d = 31.51 cm
Answer for part (b): 31.5 cm
The diagram was not attached, so these answers depend on the angle definitions stated above.