Constructing a Third degree polynomial

Question

Third-degree, with zeros of -4, -1, and 3 and a y-intercept of -7

Answer 1

a(x+4)(x+1)(x-3) =- 7

x=0

a(4(1)-3) = -7

a = -7/-12=7/12

(7/12)(x+4)(x+1)(x-3) is the cubic you want

Answer 2

y = a(x +4)(x + 1)(x - 3); x = 0; y = a(- 12) = - 7; a = 7/12

Answer: y = 7/12(x + 4)(x + 1)(x - 3)