
Bradford T. answered 09/29/22
Retired Engineer / Upper level math instructor
For a linear model the equation will be:
y(t) = at + b
Where y is the number of students enrolled, a is the number of students added per year and b is the initial number of students at t=0.
After 8 years,
y(8) = 44115 = 8a + 40563
Solving for a, a = (44115-40563)/8 = 444
y(t) = 444t + 40563
The slope is 444 which is the number of students added each year after 2000.