A mass of 27g of liquid is put into a S.G bottle at 18°C. When heated to a temperature 5g of the liquid was expelled.If the apparent expansivity of the liquid is 0.000997K/^1.Calculate the temperature

Question

Temperature

Answer 1

It's not clear what you mean by expansivity from the units. The usual expansion coefficient is (1/V)(dV/dT) which has units of K^-1. Another possibility is a linear volumetric coefficient of expansion like V = V₀ + V₀β(T-T₀) (also with K^-1 units. Finally the expansivity could be the volume change/temperature change in unit of liters/K.

In the first, dV = VαdT or integrating we obtain ln(V/V₀) = α(T-T₀)

In the second V = V₀(1 + α(T-T₀))

Either way you set n_out/n₀ = (V-V₀)/V₀ at constant pressure

In the second case this works nicely to 5g/27g = V₀α(T-T₀)/V₀ = α(T-T₀) and you can solve for T

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