Inactive Tutor answered 09/19/22
a) W = 32.0 N
u = 0.699
Normal force = 32.0 N in the Upward direction
b) Friction Force = u.N = 0.699 x 32.0 =22.368 N
c) Tension = Friction Force = 22.368 N
Andrew E.
asked 09/19/22A rope is pulling horizontally to the right on a box of weight 32.0 N which is sliding across the floor at a constant speed. The coefficient of kinetic friction between the floor and the box is 0.699.
A) What is the magnitude and direction of the normal force from the floor acting on the box?
B) What is the magnitude and direction of the frictional force acting on the box?
C) What is the magnitude of the tension in the rope which is pulling the box?
Inactive Tutor answered 09/19/22
a) W = 32.0 N
u = 0.699
Normal force = 32.0 N in the Upward direction
b) Friction Force = u.N = 0.699 x 32.0 =22.368 N
c) Tension = Friction Force = 22.368 N
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Andrew E.
Thank you!09/19/22