Justin G.

asked • 09/15/22

Newton's 2nd Law Based Question

A proton in a particle accelerator moves in a straight line as its speed increases from 2.61 × 105 m/s to 7.8 × 105 m/s as it travels a distance of 18.3 cm with constant acceleration.


I got 7.93 * 10 ^-15 and that is marked wrong but I'm not sure if it is a rounding error or I am completely wrong.

Ila G.

tutor
You should include units in the final answer. If you are trying to find the acceleration, we need to use the equation v^2=u^2+2as. Here u=2.61*10^5 m/s, v=7.8*10^5 m/s and s=18.3 cm=0.183 m. The acceleration is a=(v^2-u^2)/(2*s)= 1.47*10^12 m/s^2. Now if you are trying to find time, then we further need to use equation v=u+at. This gives time t=(v-u)/a=3.5*10^-7 sec
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09/16/22

1 Expert Answer

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Steve D. answered • 09/17/22

Tutor
New to Wyzant

PhD in Physics

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Your answer may have been marked wrong because you did not supply the units.


Also, notice that the way that you have worded the question doesn't actually state the question. Are you asked to provide the acceleration, the amount of time required for the change in speed, or some other quantity?

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