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find equation of a parabola f(x)=v4-x^2

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I'm not sure if I'm reading this question correctly. The equation y = sqrt(4-x^2) is a semicircle, it simplifies to y^2 = 4 - x^2 --->  y^2+x^2=4 (This is the equation of a circle with radius 2, but since we are only taking the positive sqrt, it is the half of the circle in the positive y axis.)


If the equation is y = v4-x^2, then this is already the equation of a parabola.  With the general form being  y = a(x-h)^2 + k, a = -1, h = 0, k = v4.