Raymond B. answered 09/07/22
Math, microeconomics or criminal justice
2/(x-5) - (x+1)/(x-4) = 6/(x^2 -x -20)
2/(x-5) - (x+1)/(x-4) = 6/(x-5)(x+4)
multiply both sides by (x-5)(x+4) to eliminate fractions:
2(x+4) - (x+1)(x-5) = 6
2x+8 -(x^2 -4x-5) = 6
-x^2 +6x -7=0
x^2 -6x +7=0
(x-7)(x+1) = 0
x= -1, 7
check x=-1
2/(-1-5) - (-1+1)/(-1-5) = 6/(-1-5)(-1+4)
-1/3 + 0 = 6/(-2)(-3) = -1/3
check x =7
2/(7-5) -(7+1)/(7+4) = 6/(7-5)(7+4)
1 - = 6/(2)(11)
11/11 -8/11 = 3/11
11-8=3