x = 1/2 g t^2
10-1.3 = 1/2 * 9.8 * t^2
t = 1.33 s
1.33 * 20.5 = 27.3
John H.
asked 09/07/22Secret Agent 006.5 (sadly, not quite as good as 007) is standing on a 10.0 tall bridge looking to escape! He sees a pick-up truck approaching, where the bed of the truck is 1.3 above the ground. The hidden radar in his glasses measures that the truck is approaching at 20.5 m/s with the cruise control on. Fortunately, the radar can also tell him how far away the truck is. How far away will the truck be when the agent should drop down from the bridge and safely land in the truck's bed?
x = 1/2 g t^2
10-1.3 = 1/2 * 9.8 * t^2
t = 1.33 s
1.33 * 20.5 = 27.3
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