distance of Bill + distance of John = 16.1
1/2 a t^2 + v t = 16.1
1/2 * 1.5 * t^2 + 5.3 * t = 16.1
t = ....
After you find t, you can find the distance by 1/2 a t^2
John H.
asked 09/07/22Initially at rest, John catches a football at the 20 yard line, and immediately begins running forward with an acceleration of 1.5 m/s/s. At the instant John caught the ball, Bill (a player on the other team) happens to be 16.1 m away and he is running directly toward John at a constant 5.3 m/s. If the players run directly toward each other, then how far from the 20 yard line will Bill tackle John?
distance of Bill + distance of John = 16.1
1/2 a t^2 + v t = 16.1
1/2 * 1.5 * t^2 + 5.3 * t = 16.1
t = ....
After you find t, you can find the distance by 1/2 a t^2
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