Mark M. answered 08/26/22
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Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = √(3x-5) Domain = {x l 3x-5 ≥ 0} = {x l x ≥ 5/3}
f(x) = 4 / (x2 - 9) Domain = {x l x2 - 9 ≠ 0} = {x l x ≠ 3, -3}
Mark M.
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I assumed that the questioner was careless with parentheses.
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08/27/22
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For the second problem it looks like only x^2 is in the denominator. So the domain is x <> 008/26/22