Mark M. answered 08/26/22
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = √(3x-5) Domain = {x l 3x-5 ≥ 0} = {x l x ≥ 5/3}
f(x) = 4 / (x2 - 9) Domain = {x l x2 - 9 ≠ 0} = {x l x ≠ 3, -3}

Mark M.
08/27/22
Kaylee S.
asked 08/26/22f(x)=6√3x-5
f(x)= 4/x2-9
Please help me. I am struggling.
Mark M. answered 08/26/22
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = √(3x-5) Domain = {x l 3x-5 ≥ 0} = {x l x ≥ 5/3}
f(x) = 4 / (x2 - 9) Domain = {x l x2 - 9 ≠ 0} = {x l x ≠ 3, -3}
Mark M.
08/27/22
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Marina M.
For the second problem it looks like only x^2 is in the denominator. So the domain is x <> 008/26/22