Eliot supplied 2000 calories of heat to 500 grams of lead at 25°C.

Question

What is the final temperature of the lead? The specific heat capacity of lead is 0.031 cal/g°C.

Answer 1

You want to utilize the equation:

where Q is the heat, m is the mass, C_p is the specific heat capacity, and ΔT is the temperature change.

In this case, Q = 2000 calories, m = 500 grams, and C_p = 0.031 cal/(g°C) so:

2000 = (500)(0.031)ΔT

2000 = 15.5ΔT

ΔT = 2000/15.5 = 129 °C

Since the temperature started at 25°C, the final temp is 25 + 129 = 154 °C

I'll let you decide how to round based on sig figs.