Mark M. answered 08/10/22
Mathematics Teacher - NCLB Highly Qualified
cos4 (2x)
[cos2 (2x)][cos2 (2x)]
[(1 + cos 4x) / 2][(1 + cos 4x) / 2]
(1 + 2 cos 4x + cos2 4x) / 4
[(1 + 2 cos 4x) / 4] + [(cos2 4x) / 4]
cos2 4x = (1 + cos 8x) / 2
[(1 + 2 cos 4x) / 4] + [((1 + cos 8x) / 2) / 4]
[(1 + 2 cos 4x) / 4] + [(1 + cos 8x) / 8]
[2(1 + 2 cos 4x) / 8] + [(1 + cos 8x) / 8]
[2 + 4 cos 4x) / 8] + [(1 + cos 8x) / 8]
[3 + 4 cos 4x + cos 8x] / 8