The technique for f(g(0)) is to put in 0 for x in g(x), and then plug in that g(0) for x in f(x):
g(0) = 1-(0)2 = 1 f(g(0)) = 6(1)-4 = 2
I'll leave the 2nd one for you.
May S.
asked 08/03/22The technique for f(g(0)) is to put in 0 for x in g(x), and then plug in that g(0) for x in f(x):
g(0) = 1-(0)2 = 1 f(g(0)) = 6(1)-4 = 2
I'll leave the 2nd one for you.
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