Robert S. answered • 07/29/22
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Remember that SHM is described by the following:
acceleration = -(ω)2(displacement), where omega is the angular frequency of motion. Since this is a straight line, displacement = distance extended from equilibrium. I assume that the .350 mm mentioned is this distance from equilibrium, so the problem simply becomes solving for angular frequency, which is thus sqrt(5.84/.35).
Robert S.
So yes, apologies I didn't catch on when it said that it was the frequency of motion and not angular frequency of motion. In that case, the relationship between angular frequency and frequency is (omega) = 2*pi*f, and so the answer before is the same, but divided by 2*pi.
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07/29/22
Gabriel R.
sorry, it was wrong. the answer was 0.650Hz07/29/22