
Robert K. answered 07/19/22
Experienced Math Tutor Who Will Improve Both Understanding and Grades
For problem 24.
Amplitude = 5
Period = 2pi/3
Phase Shift is pi/4 to the left.
Harun L.
asked 07/17/2224. Find the amplitude, period, and phase shift of the given function: y = 5 sin [3(x+ π 4 )]
25. Find the exact value of y, or state that y is undefined:
(a) y = cos−1 (√ 3/2)
(b) y = csc−1 √ 2
(c) y = cos−1 (cos(− π/3))
(d) y = sin(tan−1 7x)
(e) y = cot(sin−1 5x/9)
(f) y = cot(sin−1 c/d)
26. Simplify the algebraic expression by using the given trigonometric substitution. Assume 0 < θ < π/2: y = root of 5x/√ 49−x2, x = 7 cosθ
Robert K. answered 07/19/22
Experienced Math Tutor Who Will Improve Both Understanding and Grades
For problem 24.
Amplitude = 5
Period = 2pi/3
Phase Shift is pi/4 to the left.
Raymond B. answered 07/18/22
Math, microeconomics or criminal justice
add 2pi(n) to the following answers where n= any integer
also some likely other angles in other quadrants
question 25
a +pi/6
b pi/4 or 3pi/4
c +pi/3
d 7x/sqr(49x^2 +1)
e sqr(81-25x^2)/9
f sqr(d^2-c^2)/d
26 5x/sqr(49 -x^2) x= 7cosT
= 35cosT/(49-49cos^2(T)
=(35/49)cosT/1-cos^2(T))
=(5/7)cosT/sin^2(T)
square root of above
=sinTsqr(5costT/7)
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Robert K.
I believe c should be pi/3. I believe e should be sqr(81 - 25x^2)/9 I believe f should be sqr(d^2 - c^2)/d07/19/22