An iron vat is 18 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?

Answer 1

Explanation :



We know that

The law of thermal expansion for relative small intervals of temparatures is:

Delta(L)/LO = alpha*delta(T)........... (A)

where delta is the variation, L the length, T the temperature and alpha the coefficient of thermal liniar expansion

Given

alpha_iron = 11.1*10^-6 (1/Celsius)

LO=18

Putting values in (A)

Delta(L) = LO*alpha_iron*(100-20)

=18*11.1*10^-6*80 =0.01598 m

So,

L=LO+delta(L) = 18+0.01598=18.01598m

L=18.01598m