
Anthony T. answered 07/19/22
Patient Science Tutor
This problem can be solved using Bernoulli's equation which is
P2 + H2 x ρ x g + 1/2 x ρ x V22 = P1 + H1 x ρ x g +1/2 x ρ x V22
where P2 and P2 are the pressures of the thick end and fine end respectively, ρ is the density of water in kg /m3, g is the acceleration of gravity 9.8 m/s2, and V2 and V1 are the velocities of the water at the thick end and fine end respectively.
We are given the velocity of water at the thick end 9 m/s. We need to determine the velocity at the fine end.
The volume flow of the water can be obtained by V2 x area of thick end. This is 9 m/s x π x 0.032 which calculates to 2.54 x 10-2 m3 /s. Since water is essentially an incompressible fluid, the volume flow at the fine end must be the same as at the thick end. Use V1 = 2.54 x 10-2 / π x 0.012 = 80.89 m/s.
Now rearrange the Bernoulli equation to ΔP = P2 - P1 = ρ x g x (H1 - H2) +1/2 x ρ x (V12 - V22).
Substituting known values ΔP = 997 kg/m3 x 9.8 m/s x (0 - 6 m) + 1/2 x 997 kg/m3 x (80.892 - 92) = 3.2 x 106 Newtons / m2. Since this is a positive quantity, the thick end has a higher pressure.
Please check all calculations.