for f(x)=3x+1 and g(x) =x^2-6, find (fg)(x)

Answer 1

Answer 2

f(g(x)) = f(x^2-6)

= 3(x^2-6) +1

= 3x^2 -18+1

= 3x^2 -17

Unless by fg(x) you meant f(x)g(x)

then it

= (3x+1)(x^2-6)

= 3x^3 +x^2 -18x -6