Coulombic force is keQ1Q2/d2 Holding charges constant, FE is proportional to 1/d2 or
FE2/FE1 = (d1/d2)2
You are told that d2/d1 = 2 , therefore the ratio of the forces is (1/2)2 = 1/4
Rer A.
asked 06/13/22a. its reduced by a factor of 2.
Coulombic force is keQ1Q2/d2 Holding charges constant, FE is proportional to 1/d2 or
FE2/FE1 = (d1/d2)2
You are told that d2/d1 = 2 , therefore the ratio of the forces is (1/2)2 = 1/4
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.